代码

#include<stdio.h>
#include<stdlib.h> 
#include<math.h>

using namespace std;
const int MAX = 100;
const int  m = 7, n = 6;
int C[MAX][MAX];    // C[i][j]：Xi和Yj的LCS长度 
int X[m] = {'A', 'B', 'C', 'B', 'D', 'A', 'B'}, Y[n] = {'B', 'D', 'C', 'A', 'B', 'A'};

void LCS(int X[], int Y[], int m, int n){
    int i, j;
    char B[MAX][MAX];    // B[i][j]：C[i][j]取得最大值的标志
    for (i = 1; i <= m; i++)
        C[i][0] = 0;
    for (i = 1; i <= n; i++)
        C[0][i] = 0;
    for (i = 1; i <= m; i++){
        for (j = 1; j <= n; j++){
            if (X[i] == Y[j]){
                C[i][j] = C[i - 1][j - 1] + 1;
                B[i][j] = 'lu';
            } else if (C[i-1][j] >= C[i][j-1]){
                C[i][j] = C[i - 1][j];
                B[i][j] = 'u';
            } else {
                C[i][j] = C[i][j - 1];
                B[i][j] = 'l';
            }
        }
    }
    
    printf("\nC[i][j]\n");
    for (i = 1; i <= m; i++){
        printf("%d\t", i);
        for (j = 1; j <= n; j++){
            printf("%d\t", C[i][j]);
        }
        printf("\n");
    }
    
    printf("\nB[j][j]\n");
    for (i = 1; i <= m; i++){
        printf("%d\t", i);
        for (j = 1; j <= n; j++){
           printf("%c\t", B[i][j]);
        }
         printf("\n");
    }
}

int main () {
    LCS(X, Y, m, n);
    return 0;
    system("pause");
}